What is the solution for 2yln(x)ln(y)dx+dy=0 ?

The solution for 2yln(x)ln(y)dx+dy=0 is y=e^{e^{2x+c_{1}}x^{-2x}}

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2yln(x)ln(y)dx+dy=0

2 y ln (x) ln (y) d x + d y = 0

y = e^{e^{2 x + c_{1}} x^{- 2 x}}

Solution steps

2 y ln (x) ln (y) d x + d y = 0

Solve separable ODE:

y = e^{e^{2 x + c_{1}} x^{- 2 x}}

y = e^{e^{2 x + c_{1}} x^{- 2 x}}

(4 - 2 x^{2})^{3}

x^{^{'''}} + x^{^{''}} = 0

\int \frac{( x ^{2} + 1 )}{( x ^{2} - 2 x + 2 ) ^{2}} d x

\int sin^{2} (5 x) cos^{2} (5 x) d x

(t + 1)^{\frac{2}{3}} (3 t^{2} - 2)^{3}

What is the solution for 2yln(x)ln(y)dx+dy=0 ?
The solution for 2yln(x)ln(y)dx+dy=0 is y=e^{e^{2x+c_{1}}x^{-2x}}