What is the integral from 0 to 1 of cos(2x) ?

The integral from 0 to 1 of cos(2x) is 1/2 sin(2)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from 0 to 1 of cos(2x)

\int_{0}^{1} cos (2 x) d x

\frac{1}{2} sin (2)

Solution steps

\int_{0}^{1} cos (2 x) d x

Apply u-substitution

: \int_{0}^{2} cos (u) \frac{1}{2} d u

= \int_{0}^{2} cos (u) \frac{1}{2} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{2} \cdot \int_{0}^{2} cos (u) d u

Use the common integral:

\int cos (u) d u = sin (u)

= \frac{1}{2} [sin (u)]_{0}^{2}

Compute the boundaries:

sin (2)

= \frac{1}{2} sin (2)

\frac{\partial}{\partial y} (\frac{5}{2} x^{2} + 4 x y)

\int \frac{t}{1 - t ^{8}} d t

\frac{\partial}{\partial x} ((x - y)^{10})

x^{4}, x^{2}

f (x) = d e^{- c x}

What is the integral from 0 to 1 of cos(2x) ?
The integral from 0 to 1 of cos(2x) is 1/2 sin(2)