integral from 0 to 8 of (16x-128)

Lösung

\int_{0}^{8} (16 x - 128) d x

- 512

Schritte zur Lösung

\int_{0}^{8} 16 x - 128 d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{8} 16 x d x - \int_{0}^{8} 128 d x

\int_{0}^{8} 16 x d x = 512

\int_{0}^{8} 128 d x = 1024

= 512 - 1024

Vereinfache

= - 512

\int_{0}^{2} x^{3} sin (x) d x

\int_{0}^{2} 8 x - x^{2} d x

\int_{- 1}^{2} 3 x + 6 d x

\int_{- π}^{π} (1 + x) sin (n x) d x

\int_{0}^{5} (2 e^{x}) d x