integral from 0 to 3 of 3x^2-12x+9

Lösung

\int_{0}^{3} 3 x^{2} - 12 x + 9 d x

0

Schritte zur Lösung

\int_{0}^{3} 3 x^{2} - 12 x + 9 d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{3} 3 x^{2} d x - \int_{0}^{3} 12 x d x + \int_{0}^{3} 9 d x

\int_{0}^{3} 3 x^{2} d x = 27

\int_{0}^{3} 12 x d x = 54

\int_{0}^{3} 9 d x = 27

= 27 - 54 + 27

Vereinfache

= 0

\int_{1}^{10} \frac{ln ( x )}{x} d x

\int_{0}^{x} e^{- t^{4}} d t

\int_{0}^{1} e^{2 x} + \frac{3}{x ^{2} + 1} d x

\int_{0}^{5} 10 + 4 x - x^{2} d x

\int_{1}^{3} 3^{x} d x