integral from 0 to 1 of tcosh(t)

Lösung

\int_{0}^{1} t cosh (t) d t

- \frac{1}{e} + 1

Dezimale

0.63212 \dots

Schritte zur Lösung

\int_{0}^{1} t cosh (t) d t

Wende die partielle Integration an

= [t sinh (t) - \int sinh (t) d t]_{0}^{1}

\int sinh (t) d t = cosh (t)

= [t sinh (t) - cosh (t)]_{0}^{1}

Berechne die Grenzen:

- \frac{1}{e} + 1

= - \frac{1}{e} + 1

\int_{0}^{t^{4}} u^{7} d u

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