integral from 2 to 3 of-t^2+2t+3

Lösung

\int_{2}^{3} - t^{2} + 2 t + 3 d t

\frac{5}{3}

Dezimale

1.66666 \dots

Schritte zur Lösung

\int_{2}^{3} - t^{2} + 2 t + 3 d t

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= - \int_{2}^{3} t^{2} d t + \int_{2}^{3} 2 t d t + \int_{2}^{3} 3 d t

\int_{2}^{3} t^{2} d t = \frac{19}{3}

\int_{2}^{3} 2 t d t = 5

\int_{2}^{3} 3 d t = 3

= - \frac{19}{3} + 5 + 3

Vereinfache

- \frac{19}{3} + 5 + 3 : \frac{5}{3}

= \frac{5}{3}

\int_{- 1}^{1} (x)^{2} d x

\int_{0}^{x^{2}} cos (t^{3}) d t

\int_{0}^{\frac{π}{3}} 2 cos (x) d x

\int_{0}^{2} 5^{3 x} d x

\int_{0}^{2} (2 x^{3} - 2 x) d x