integral from-1 to 7 of xsqrt(2+x)

Lösung

\int_{- 1}^{7} x 2 + x d x

\frac{932}{15}

Dezimale

62.13333 \dots

Schritte zur Lösung

\int_{- 1}^{7} x 2 + x d x

Wende U-Substitution an

= \int_{1}^{9} (u - 2) u d u

Multipliziere aus

(u - 2) u : u^{\frac{3}{2}} - 2 u

= \int_{1}^{9} u^{\frac{3}{2}} - 2 u d u

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{1}^{9} u^{\frac{3}{2}} d u - \int_{1}^{9} 2 u d u

\int_{1}^{9} u^{\frac{3}{2}} d u = \frac{484}{5}

\int_{1}^{9} 2 u d u = \frac{104}{3}

= \frac{484}{5} - \frac{104}{3}

Vereinfache

\frac{484}{5} - \frac{104}{3} : \frac{932}{15}

= \frac{932}{15}

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