integral from 0 to pi of 2+2cos(x)

Lösung

\int_{0}^{π} 2 + 2 cos (x) d x

2 π

Dezimale

6.28318 \dots

Schritte zur Lösung

\int_{0}^{π} 2 + 2 cos (x) d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{π} 2 d x + \int_{0}^{π} 2 cos (x) d x

\int_{0}^{π} 2 d x = 2 π

\int_{0}^{π} 2 cos (x) d x = 0

= 2 π + 0

Vereinfache

= 2 π

\int_{- 1}^{1} 2 x 1 - x^{2} d x

\int_{1}^{2} 3 x d x

\int_{0}^{2} (3 x^{2} + x - 5) d x

\int_{0}^{2 π} sin (x) cos (2 x) d x

\int_{0}^{1} 4 x e^{x^{2}} d x