integral from 4 to 8 of 1/(sqrt(x-4))

Lösung

\int_{4}^{8} \frac{1}{x - 4} d x

4

Schritte zur Lösung

\int_{4}^{8} \frac{1}{x - 4} d x

Wende U-Substitution an

= \int_{0}^{2} 2 d u

Integral einer Konstanten :

\int a d x = a x

= [2 u]_{0}^{2}

Berechne die Grenzen:

4

= 4

\int_{0}^{1} 4 x + 1 d x

\int_{1}^{2} \frac{2 x}{( x ^{2} + 1 ) ^{3}} d x

\int_{4}^{25} \frac{1}{x} d x

\int_{- 3}^{3} \frac{x y ^{2}}{x ^{2} + 1} d y

\int_{2}^{7} ln (x) d x