What is the first derivative of 20-2x ?

The first derivative of 20-2x is -2

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derivative of 20-2x

\frac{d}{d x} (20 - 2 x)

- 2

Solution steps

\frac{d}{d x} (20 - 2 x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (20) - \frac{d}{d x} (2 x)

\frac{d}{d x} (20) = 0

\frac{d}{d x} (2 x) = 2

= 0 - 2

Simplify

= - 2

\frac{d}{d x} (\frac{x ^{4}}{8} ln (x) - \frac{x ^{4}}{32})

t an g e n t y = \frac{8}{x + 1}

x \to 0 lim (x \cdot e^{\frac{1}{x}})

\frac{d}{d x} (\frac{cos ( 2 x )}{x})

\frac{\partial}{\partial x} (ln (\frac{( x + y )}{x - y}))