What is the derivative of 2/((x-1^3)) ?

The derivative of 2/((x-1^3)) is -6/((x-1)^4)

What is the first derivative of 2/((x-1^3)) ?

The first derivative of 2/((x-1^3)) is -6/((x-1)^4)

\frac{d}{d x} (\frac{2}{( x - 1 ) ^{3}})

- \frac{6}{( x - 1 ) ^{4}}

Solution steps

\frac{d}{d x} (\frac{2}{( x - 1 ) ^{3}})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 \frac{d}{d x} (\frac{1}{( x - 1 ) ^{3}})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= 2 \frac{d}{d x} ((x - 1)^{- 3})

Apply the chain rule:

- \frac{3}{( x - 1 ) ^{4}} \frac{d}{d x} (x - 1)

= - \frac{3}{( x - 1 ) ^{4}} \frac{d}{d x} (x - 1)

\frac{d}{d x} (x - 1) = 1

= 2 (- \frac{3}{( x - 1 ) ^{4}} \cdot 1)

Simplify

2 (- \frac{3}{( x - 1 ) ^{4}} \cdot 1) : - \frac{6}{( x - 1 ) ^{4}}

= - \frac{6}{( x - 1 ) ^{4}}

in v erse l a pl a ce \frac{2 \cdot ( s - 1 ) \cdot e ^{- 2 s}}{s ^{2} - 2 s + 2}

t an g e n t y = x^{2} + 2, (- 4, 18)

a re a y = 7 x, y = \frac{7}{4} x, y = 78 - x^{2}

\int - \frac{1}{50} d x

\int_{0}^{1} \frac{5 x ^{4}}{1 + x ^{5}} d x

What is the derivative of 2/((x-1^3)) ?
The derivative of 2/((x-1^3)) is -6/((x-1)^4)
What is the first derivative of 2/((x-1^3)) ?
The first derivative of 2/((x-1^3)) is -6/((x-1)^4)