What is the limit as x approaches 0+of arctan(ln(x)) ?

The limit as x approaches 0+of arctan(ln(x)) is -pi/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

limit as x approaches 0+of arctan(ln(x))

x \to 0 + lim (arctan (ln (x)))

- \frac{π}{2}

Decimal

- 1.57079 \dots

Solution steps

x \to 0 + lim (arctan (ln (x)))

Apply the Limit Chain Rule:

- \frac{π}{2}

= - \frac{π}{2}

\frac{d v}{d x} - \frac{1}{x} v = 8

d er i v a t i v e \frac{ln ( x )}{e ^{x}}

\int x e^{- x (y + 1)} d x

\int (3 x^{2} + 1)^{3} d x

\frac{d y}{d x} + y cos (x) = 2 cos (x), y (0) = 4

What is the limit as x approaches 0+of arctan(ln(x)) ?
The limit as x approaches 0+of arctan(ln(x)) is -pi/2