What is the derivative of y=-4log_{5}(x) ?

The derivative of y=-4log_{5}(x) is -4/(ln(5)x)

What is the first derivative of y=-4log_{5}(x) ?

The first derivative of y=-4log_{5}(x) is -4/(ln(5)x)

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derivative of

y = - 4 lo g_{5} (x)

- \frac{4}{ln ( 5 ) x}

Solution steps

\frac{d}{d x} (- 4 lo g_{5} (x))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - 4 \frac{d}{d x} (lo g_{5} (x))

Apply the derivative log rule:

\frac{d}{d x} (lo g_{a} (x)) = \frac{1}{x ln ( a )}

= - 4 \cdot \frac{1}{x ln ( 5 )}

Simplify

- 4 \cdot \frac{1}{x ln ( 5 )} : - \frac{4}{ln ( 5 ) x}

= - \frac{4}{ln ( 5 ) x}

\frac{d}{d x} (e^{3 x} + e^{x + e^{- 2 x}})

\int_{1}^{e} t^{2} ln (t) d t

\frac{x - 3}{x}

\int \frac{1}{x ^{2} + 4 x + 2} d x

x^{3} y^{^{'}} + 2 x^{2} y = 4 cos (4 x) y^{- \frac{1}{2}}

What is the derivative of y=-4log_{5}(x) ?
The derivative of y=-4log_{5}(x) is -4/(ln(5)x)
What is the first derivative of y=-4log_{5}(x) ?
The first derivative of y=-4log_{5}(x) is -4/(ln(5)x)