integral of 9xarcsec(x)

Lösung

\int 9 x arcsec (x) d x

9 (\frac{1}{2} x^{2} arcsec (x) - \frac{1}{2} x^{2} - 1) + C

Schritte zur Lösung

\int 9 x arcsec (x) d x

Entferne die Konstante:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 9 \cdot \int x arcsec (x) d x

Wende die partielle Integration an

= 9 (\frac{1}{2} x^{2} arcsec (x) - \int \frac{x ^{2}}{2 x ^{2} x ^{2} - 1} d x)

\int \frac{x ^{2}}{2 x ^{2} x ^{2} - 1} d x = \frac{1}{2} x^{2} - 1

= 9 (\frac{1}{2} x^{2} arcsec (x) - \frac{1}{2} x^{2} - 1)

Füge eine Konstante zur Lösung hinzu

= 9 (\frac{1}{2} x^{2} arcsec (x) - \frac{1}{2} x^{2} - 1) + C

\int cos (2 x) + sin (2 x) d x

\int - 10 x^{- 11} d x

\int 12 y^{3} d y

\int 3 + y^{2} d y

\int \frac{2}{( x ^{2} + 2 x + 2 ) ^{2}} d x