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Beliebt Rechnen >

integral of (10x)/(x^2+7x+6)

Lösung

\int \frac{10 x}{x ^{2} + 7 x + 6} d x

Lösung

5 ln 4 x^{2} + 28 x + 24 + 7 ln \frac{12}{5} + \frac{2}{5} x - 7 ln \frac{2}{5} + \frac{2}{5} x + C

Schritte zur Lösung

\int \frac{10 x}{x ^{2} + 7 x + 6} d x

Entferne die Konstante:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 10 \cdot \int \frac{x}{x ^{2} + 7 x + 6} d x

Vervollständige das Quadrat

x^{2} + 7 x + 6 : (x + \frac{7}{2})^{2} - \frac{25}{4}

= 10 \cdot \int \frac{x}{( x + \frac{7}{2} ) ^{2} - \frac{25}{4}} d x

Wende U-Substitution an

= 10 \cdot \int \frac{2 ( 2 u - 7 )}{4 u ^{2} - 25} d u

Entferne die Konstante:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 10 \cdot 2 \cdot \int \frac{2 u - 7}{4 u ^{2} - 25} d u

Multipliziere aus

\frac{2 u - 7}{4 u ^{2} - 25} : \frac{2 u}{4 u ^{2} - 25} - \frac{7}{4 u ^{2} - 25}

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= 10 \cdot 2 (\int \frac{2 u}{4 u ^{2} - 25} d u - \int \frac{7}{4 u ^{2} - 25} d u)

\int \frac{2 u}{4 u ^{2} - 25} d u = \frac{1}{4} ln 4 u^{2} - 25

\int \frac{7}{4 u ^{2} - 25} d u = - \frac{7}{20} (ln \frac{2}{5} u + 1 - ln \frac{2}{5} u - 1)

= 10 \cdot 2 (\frac{1}{4} ln 4 u^{2} - 25 - (- \frac{7}{20} (ln \frac{2}{5} u + 1 - ln \frac{2}{5} u - 1)))

Setze in

u = x + \frac{7}{2}

ein

= 10 \cdot 2 (\frac{1}{4} ln 4 (x + \frac{7}{2})^{2} - 25 - (- \frac{7}{20} (ln \frac{2}{5} (x + \frac{7}{2}) + 1 - ln \frac{2}{5} (x + \frac{7}{2}) - 1)))

Vereinfache

10 \cdot 2 (\frac{1}{4} ln 4 (x + \frac{7}{2})^{2} - 25 - (- \frac{7}{20} (ln \frac{2}{5} (x + \frac{7}{2}) + 1 - ln \frac{2}{5} (x + \frac{7}{2}) - 1))) : 5 ln 4 x^{2} + 28 x + 24 + 7 ln \frac{12}{5} + \frac{2}{5} x - 7 ln \frac{2}{5} + \frac{2}{5} x

= 5 ln 4 x^{2} + 28 x + 24 + 7 ln \frac{12}{5} + \frac{2}{5} x - 7 ln \frac{2}{5} + \frac{2}{5} x

Füge eine Konstante zur Lösung hinzu

= 5 ln 4 x^{2} + 28 x + 24 + 7 ln \frac{12}{5} + \frac{2}{5} x - 7 ln \frac{2}{5} + \frac{2}{5} x + C

Graph

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