What is the solution for 1296y^{''}+1368y^'+361y=0 ?

The solution for 1296y^{''}+1368y^'+361y=0 is y=c_{1}e^{-(19t)/(36)}+c_{2}e^{-(19t)/(36)}t

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1296y^{''}+1368y^'+361y=0

1296 y^{^{''}} + 1368 y^{^{'}} + 361 y = 0

y = c_{1} e^{- \frac{19 t}{36}} + c_{2} e^{- \frac{19 t}{36}} t

Solution steps

1296 y^{''} (t) + 1368 y^{'} (t) + 361 y = 0

Solve linear ODE:

y = c_{1} e^{- \frac{19 t}{36}} + c_{2} e^{- \frac{19 t}{36}} t

y = c_{1} e^{- \frac{19 t}{36}} + c_{2} e^{- \frac{19 t}{36}} t

x \frac{d y}{d x} = y + (x^{2} - 2)^{2}

\int sin^{2} (π x) cos^{5} (π x) d x

\frac{d}{d x} (csc^{2} (1 - 2 x))

x \to - 1 lim (3 x^{4} - 6 x + 1)

What is the solution for 1296y^{''}+1368y^'+361y=0 ?
The solution for 1296y^{''}+1368y^'+361y=0 is y=c_{1}e^{-(19t)/(36)}+c_{2}e^{-(19t)/(36)}t