What is the limit as x approaches 0+of sqrt(1/x) ?

The limit as x approaches 0+of sqrt(1/x) is infinity

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limit as x approaches 0+of sqrt(1/x)

x \to 0 + lim (\frac{1}{x})

\infty

Solution steps

x \to 0 + lim (\frac{1}{x})

x \to a lim [f (x)]^{b} = [x \to a lim f (x)]^{b}

With the exception of indeterminate form

= x \to 0 + lim (\frac{1}{x})

For

x

approaching

0

from the right

, x > 0 \Rightarrow x > 0

The denominator is a positive quantity approaching 0 from the right

= \infty

Apply Infinity Property:

\infty^{c} = \infty

= \infty

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\frac{d}{d x} (tan (2 x^{3}))

\int \frac{x}{x ^{4} - 16 x ^{2} + 39} d x

What is the limit as x approaches 0+of sqrt(1/x) ?
The limit as x approaches 0+of sqrt(1/x) is infinity