de

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Beliebt Rechnen >

sum from n=1 to infinity of 5/(4n^2-1)

Lösung

n = 1 \sum \infty \frac{5}{4 n ^{2} - 1}

Lösung

\frac{5}{2}

+1

Dezimale

2.5

Schritte zur Lösung

n = 1 \sum \infty \frac{5}{4 n ^{2} - 1}

Wende die Regel der konstanten Multiplikation:

\sum c \cdot a_{n} = c \cdot \sum a_{n}

= 5 \cdot n = 1 \sum \infty \frac{1}{4 n ^{2} - 1}

Teleskopreihen-Test anwenden:

\frac{1}{2}

= 5 \cdot \frac{1}{2}

Vereinfache

5 \cdot \frac{1}{2} : \frac{5}{2}

= \frac{5}{2}

Beliebte Beispiele

integral from 1/5 to 7 of 8xln(5x)

\int_{\frac{1}{5}}^{7} 8 x ln (5 x) d x

y^{^{'}} + \frac{2}{x} y = 4 x

derivative of ln(7x^2+5y^2)

\frac{d}{d x} (ln (7 x^{2} + 5 y^{2}))

derivative 4t^{(-1)/8}+5ln(t)+ln(5)

d er i v a t i v e 4 t^{\frac{- 1}{8}} + 5 ln (t) + ln (5)

tangent f(x)=3x^2-4x+1

t an g e n t f (x) = 3 x^{2} - 4 x + 1