What is the solution for y^'+0.06y=6 ?

The solution for y^'+0.06y=6 is y=-(e^{-0.06t-c_{1}})/(0.06)+6/(0.06)

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y^'+0.06y=6

y^{^{'}} + 0.06 y = 6

y = - \frac{e ^{- 0.06 t - c_{1}}}{0.06} + \frac{6}{0.06}

Solution steps

y^{'} (t) + 0.06 y = 6

Solve separable ODE:

y = - \frac{e ^{- 0.06 t - c_{1}}}{0.06} + \frac{6}{0.06}

y = - \frac{e ^{- 0.06 t - c_{1}}}{0.06} + \frac{6}{0.06}

n = 1 \sum \infty \frac{( n ! )}{n ^{n}}

y = 91

\int x^{2} (x + 1) d x

x \to - 3 lim (\frac{x + 3}{x + 4})

\int \frac{( 1 + cos ( x ) )}{sin ( x )} d x

What is the solution for y^'+0.06y=6 ?
The solution for y^'+0.06y=6 is y=-(e^{-0.06t-c_{1}})/(0.06)+6/(0.06)