What is the d/(dt)(6/5-6/5 e^{-20t}) ?

The d/(dt)(6/5-6/5 e^{-20t}) is 24e^{-20t}

What is the first d/(dt)(6/5-6/5 e^{-20t}) ?

The first d/(dt)(6/5-6/5 e^{-20t}) is 24e^{-20t}

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\frac{d}{d t} (\frac{6}{5} - \frac{6}{5} e^{- 20 t})

24 e^{- 20 t}

Solution steps

\frac{d}{d t} (\frac{6}{5} - \frac{6}{5} e^{- 20 t})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d t} (\frac{6}{5}) - \frac{d}{d t} (\frac{6}{5} e^{- 20 t})

\frac{d}{d t} (\frac{6}{5}) = 0

\frac{d}{d t} (\frac{6}{5} e^{- 20 t}) = - 24 e^{- 20 t}

= 0 - (- 24 e^{- 20 t})

Simplify

= 24 e^{- 20 t}

a re a y = x^{3} - 6 x^{2} + 9 x, y = x, x = 0, x = 2

\int_{0}^{\infty} 4 x e^{- 2 x} d x

y^{^{''}} + 3 y^{^{'}} + 2 y = 4 t

\int \frac{x}{7 x + 1} d x

d er i v a t i v e f (x) = 9 - 2 x^{2}

What is the d/(dt)(6/5-6/5 e^{-20t}) ?
The d/(dt)(6/5-6/5 e^{-20t}) is 24e^{-20t}
What is the first d/(dt)(6/5-6/5 e^{-20t}) ?
The first d/(dt)(6/5-6/5 e^{-20t}) is 24e^{-20t}