What is the sum from n=0 to infinity of (-1)^nn ?

The sum from n=0 to infinity of (-1)^nn is diverges

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sum from n=0 to infinity of (-1)^nn

n = 0 \sum \infty (- 1)^{n} n

diverges

Solution steps

n = 0 \sum \infty (- 1)^{n} n

Apply Series Divergence Test:

diverges

= diverges

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x \to 0 + lim (cos (\frac{1}{x}))

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x^{2} - 4 x + 24

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What is the sum from n=0 to infinity of (-1)^nn ?
The sum from n=0 to infinity of (-1)^nn is diverges