What is the tangent of xy=-121 ?

The tangent of xy=-121 is y=(121)/(a_{0)^2}x-(242)/(a_{0)}

tangent of xy=-121

tangent of

x y = - 121

y = \frac{121}{a _{0}^{2}} x - \frac{242}{a _{0}}

Solution steps

Compute the tangent line to the general point

x = a_{0}

Find the tangent point:

(a_{0}, - \frac{121}{a _{0}})

Find the slope of

x y = - 121 : \frac{d y}{d x} = \frac{121}{x ^{2}}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = \frac{121}{a _{0}^{2}}

Find the line with slope m=

\frac{121}{a _{0}^{2}}

and passing through

(a_{0}, - \frac{121}{a _{0}}) : y = \frac{121}{a _{0}^{2}} x - \frac{242}{a _{0}}

y = \frac{121}{a _{0}^{2}} x - \frac{242}{a _{0}}

d er i v a t i v e y = 12 e^{2} x

\frac{d}{d x} (2 x^{2} + 3 x + 2)

\int + e^{- 3 x} sin (b x) d x

\frac{d}{d x} (arcsin (\frac{x}{3}))

\int \frac{4 x + 1}{4 x} d x

What is the tangent of xy=-121 ?
The tangent of xy=-121 is y=(121)/(a_{0)^2}x-(242)/(a_{0)}