What is the d/(dt)(10sin(t)) ?

The d/(dt)(10sin(t)) is 10cos(t)

What is the first d/(dt)(10sin(t)) ?

The first d/(dt)(10sin(t)) is 10cos(t)

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\frac{d}{d t} (10 sin (t))

10 cos (t)

Solution steps

\frac{d}{d t} (10 sin (t))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 10 \frac{d}{d t} (sin (t))

Apply the common derivative:

\frac{d}{d t} (sin (t)) = cos (t)

= 10 cos (t)

\frac{d ^{2} y}{d t ^{2}} + 4 \frac{d y}{d t} + 4 y = 0

z \to 1 + i lim (z^{2} - 5 z + 10)

y^{^{'}} = 2 y - 4 x

\frac{d x}{d t} + 3 = 0

d er i v a t i v e y = (\frac{x - 1}{x ^{2} + x + 1})^{4}