What is the tangent of y=x^4+7x^2-x,(1,7) ?

The tangent of y=x^4+7x^2-x,(1,7) is y=17x-10

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tangent of y=x^4+7x^2-x,(1,7)

tangent of

y = x^{4} + 7 x^{2} - x, (1, 7)

y = 17 x - 10

Solution steps

Find the slope of

y = x^{4} + 7 x^{2} - x : \frac{d y}{d x} = 4 x^{3} + 14 x - 1

Compute the slope of

y = x^{4} + 7 x^{2} - x

(1, 7) : m = 17

Find the line with slope m=

17

and passing through

(1, 7) : y = 17 x - 10

y = 17 x - 10

\int_{0}^{2} 2 sec (\frac{π x}{6}) d x

2^{x}, 1

\int \frac{1}{θ ^{2}} sin (\frac{1}{θ}) cos (\frac{1}{θ}) d θ

\frac{d}{d t} (e^{5 t})

y = e^{9 x}

What is the tangent of y=x^4+7x^2-x,(1,7) ?
The tangent of y=x^4+7x^2-x,(1,7) is y=17x-10