What is the integral of (ln(t))/(t^2) ?

The integral of (ln(t))/(t^2) is -(ln(t))/t-1/t+C

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integral of (ln(t))/(t^2)

\int \frac{ln ( t )}{t ^{2}} d t

- \frac{ln ( t )}{t} - \frac{1}{t} + C

Solution steps

\int \frac{ln ( t )}{t ^{2}} d t

Apply Integration By Parts

= - \frac{ln ( t )}{t} - \int - \frac{1}{t ^{2}} d t

\int - \frac{1}{t ^{2}} d t = \frac{1}{t}

= - \frac{ln ( t )}{t} - \frac{1}{t}

Add a constant to the solution

= - \frac{ln ( t )}{t} - \frac{1}{t} + C

\int ln (x^{2} + 15 x + 44) d x

in v erse l a pl a ce \frac{3 ^{2}}{( s + 3 ) ^{2}} \cdot \frac{1}{s}

\int \frac{1 - w}{w} d w

\frac{\partial}{\partial v} (2 sin (u) cos (v))

d er i v a t i v e y = \frac{5 x ^{2} + 8 x + 4}{x}

What is the integral of (ln(t))/(t^2) ?
The integral of (ln(t))/(t^2) is -(ln(t))/t-1/t+C