What is the derivative of-2sin(xcos(x)) ?

The derivative of-2sin(xcos(x)) is -cos(2x)*2

What is the first derivative of-2sin(xcos(x)) ?

The first derivative of-2sin(xcos(x)) is -cos(2x)*2

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\frac{d}{d x} (- 2 sin (x) cos (x))

- cos (2 x) \cdot 2

Solution steps

\frac{d}{d x} (- 2 sin (x) cos (x))

Simplify

- 2 sin (x) cos (x) : - sin (2 x)

= \frac{d}{d x} (- sin (2 x))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - \frac{d}{d x} (sin (2 x))

Apply the chain rule:

cos (2 x) \frac{d}{d x} (2 x)

= cos (2 x) \frac{d}{d x} (2 x)

\frac{d}{d x} (2 x) = 2

= - cos (2 x) \cdot 2

n = 0 \sum \infty n \cdot x^{n}

y = 2 x + 1

\int - 2 x^{- 2} d x

\frac{d}{d θ} (sin^{3} (θ))

\frac{d}{d x} (10 (1 - e^{\frac{x}{2}}))

What is the derivative of-2sin(xcos(x)) ?
The derivative of-2sin(xcos(x)) is -cos(2x)*2
What is the first derivative of-2sin(xcos(x)) ?
The first derivative of-2sin(xcos(x)) is -cos(2x)*2