What is the solution for (dx)/(dt)=2+sqrt(x-2t+3) ?

The solution for (dx)/(dt)=2+sqrt(x-2t+3) is x=(t^2+c_{1}^2)/4+(c_{1}t)/2+2t-3

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(dx)/(dt)=2+sqrt(x-2t+3)

\frac{d x}{d t} = 2 + x - 2 t + 3

x = \frac{t ^{2} + c _{1}^{2}}{4} + \frac{c _{1} t}{2} + 2 t - 3

Solution steps

\frac{d x}{d t} = 2 + x - 2 t + 3

Solve using substitution:

x = \frac{t ^{2} + c _{1}^{2}}{4} + \frac{c _{1} t}{2} + 2 t - 3

x = \frac{t ^{2} + c _{1}^{2}}{4} + \frac{c _{1} t}{2} + 2 t - 3

\frac{d}{d x} (e^{0.2})

\frac{\partial}{\partial t} (e^{r t})

\frac{d y}{d x} = \frac{( 4 sec ( y ) )}{( x + 5 ) ^{2}}

x \to 4 lim (\frac{5}{4 - x})

\int e^{\frac{1}{t}} d t

What is the solution for (dx)/(dt)=2+sqrt(x-2t+3) ?
The solution for (dx)/(dt)=2+sqrt(x-2t+3) is x=(t^2+c_{1}^2)/4+(c_{1}t)/2+2t-3