What is the integral from-infinity to 12 of re^{r/3} ?

The integral from-infinity to 12 of re^{r/3} is 27e^4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

integral from-infinity to 12 of re^{r/3}

\int_{- \infty}^{12} r e^{\frac{r}{3}} d r

27 e^{4}

Decimal

1474.15005 \dots

Solution steps

\int_{- \infty}^{12} r e^{\frac{r}{3}} d r

Compute the indefinite integral:

\int r e^{\frac{r}{3}} d r = 3 e^{\frac{r}{3}} r - 9 e^{\frac{r}{3}} + C

Compute the boundaries:

\int_{- \infty}^{12} r e^{\frac{r}{3}} d r = 27 e^{4} - 0

= 27 e^{4} - 0

Simplify

= 27 e^{4}

What is the integral from-infinity to 12 of re^{r/3} ?
The integral from-infinity to 12 of re^{r/3} is 27e^4