What is the derivative of ln(x+2x) ?

The derivative of ln(x+2x) is 1/x+2

What is the first derivative of ln(x+2x) ?

The first derivative of ln(x+2x) is 1/x+2

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\frac{d}{d x} (ln (x) + 2 x)

\frac{1}{x} + 2

Solution steps

\frac{d}{d x} (ln (x) + 2 x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (ln (x)) + \frac{d}{d x} (2 x)

\frac{d}{d x} (ln (x)) = \frac{1}{x}

\frac{d}{d x} (2 x) = 2

= \frac{1}{x} + 2

\frac{1}{1 + x ^{2}}, 0

\int_{0}^{1} (1 - x^{7})^{2} d x

x^{3} - 2 x^{2} - 4 x + 6

y^{^{''}} - 2 y^{^{'}} = x + 2 e^{x}, y (0) = 18, y^{^{'}} (0) = \frac{31}{4}

\frac{d}{d x} (2 cos (x) + 3 sin (x))

What is the derivative of ln(x+2x) ?
The derivative of ln(x+2x) is 1/x+2
What is the first derivative of ln(x+2x) ?
The first derivative of ln(x+2x) is 1/x+2