What is (\partial)/(\partial x)(y+xcos(t)) ?

The answer to (\partial)/(\partial x)(y+xcos(t)) is cos(t)

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(\partial)/(\partial x)(y+xcos(t))

\frac{\partial}{\partial x} (y + x cos (t))

cos (t)

Solution steps

\frac{\partial}{\partial x} (y + x cos (t))

Treat

y, t

as constants

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (y) + \frac{\partial}{\partial x} (x cos (t))

\frac{\partial}{\partial x} (y) = 0

\frac{\partial}{\partial x} (x cos (t)) = cos (t)

= 0 + cos (t)

Simplify

= cos (t)

\frac{\partial}{\partial x} (tan (2 x + y))

y = \frac{x - 6}{x + 6}

\frac{d}{d x} (\frac{8}{x ^{5}})

(0, 1), (5, - 2)

\int \frac{8 - x}{8 + x} d x

What is (\partial)/(\partial x)(y+xcos(t)) ?
The answer to (\partial)/(\partial x)(y+xcos(t)) is cos(t)