What is (\partial ^2)/(\partial x\partial y)(xye^{-6y}) ?

The answer to (\partial ^2)/(\partial x\partial y)(xye^{-6y}) is -6e^{-6y}y+e^{-6y}

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(\partial ^2)/(\partial x\partial y)(xye^{-6y})

\frac{\partial ^{2}}{\partial x \partial y} (x y e^{- 6 y})

- 6 e^{- 6 y} y + e^{- 6 y}

Solution steps

\frac{\partial ^{2}}{\partial x \partial y} (x y e^{- 6 y})

\frac{\partial}{\partial x} (x y e^{- 6 y}) = e^{- 6 y} y

= \frac{\partial}{\partial y} (e^{- 6 y} y)

\frac{\partial}{\partial y} (e^{- 6 y} y) = - 6 e^{- 6 y} y + e^{- 6 y}

= - 6 e^{- 6 y} y + e^{- 6 y}

n = 1 \sum \infty \frac{2}{n ^{2} + n}

x \to 0 lim (\frac{( x - 1 ) ^{3} + 1}{h ( x )})

x \to + 1 lim (x sin (\frac{1}{x}))

\frac{\partial}{\partial y} (\frac{y}{y + x})

\int_{- 2}^{0} x + 2 d x

What is (\partial ^2)/(\partial x\partial y)(xye^{-6y}) ?
The answer to (\partial ^2)/(\partial x\partial y)(xye^{-6y}) is -6e^{-6y}y+e^{-6y}