What is the tangent of f(x)=7cos(x),\at ((2pi)/3) ?

The tangent of f(x)=7cos(x),\at ((2pi)/3) is y=-7sin(a_{0})x+7cos(a_{0})+7a_{0}sin(a_{0})

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tangent of f(x)=7cos(x),\at ((2pi)/3)

tangent of

f (x) = 7 cos (x), at (\frac{2 π}{3})

y = - 7 sin (a_{0}) x + 7 cos (a_{0}) + 7 a_{0} sin (a_{0})

Solution steps

Compute the tangent line to the general point

x = a_{0}

Find the tangent point:

(a_{0}, 7 cos (a_{0}))

Find the slope of

f (x) = 7 cos (x) : \frac{df ( x )}{d x} = - 7 sin (x)

Compute the slope of

f (x) = 7 cos (x)

x = a_{0} : m = - 7 sin (a_{0})

Find the line with slope m=

- 7 sin (a_{0})

and passing through

(a_{0}, 7 cos (a_{0})) : y = - 7 sin (a_{0}) x + 7 cos (a_{0}) + 7 a_{0} sin (a_{0})

y = - 7 sin (a_{0}) x + 7 cos (a_{0}) + 7 a_{0} sin (a_{0})

x \to 1 lim (\frac{2 - x}{x - 1})

\frac{d}{d x} (x \cdot 2)

(10.1) (5.2)

\int \frac{1}{x ^{2} - x} d x

4 s

What is the tangent of f(x)=7cos(x),\at ((2pi)/3) ?
The tangent of f(x)=7cos(x),\at ((2pi)/3) is y=-7sin(a_{0})x+7cos(a_{0})+7a_{0}sin(a_{0})