What is inverse oflaplace ((2))/((s-1)^2) ?

The answer to inverse oflaplace ((2))/((s-1)^2) is e^t*2t

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

inverse oflaplace ((2))/((s-1)^2)

inverselaplace

e^{t} \cdot 2 t

Solution steps

L^{- 1} {\frac{( 2 )}{( s - 1 ) ^{2}}}

Apply inverse transform rule:

L^{- 1} {F (s)} = f (t)

then

L^{- 1} {F (s - a)} = e^{a t} f (t)

For

\frac{2}{( s - 1 ) ^{2}} : a = 1, F (s) = \frac{2}{s ^{2}}

= e^{t} L^{- 1} {\frac{2}{s ^{2}}}

L^{- 1} {\frac{2}{s ^{2}}} : 2 t

= e^{t} \cdot 2 t

What is inverse oflaplace ((2))/((s-1)^2) ?
The answer to inverse oflaplace ((2))/((s-1)^2) is e^t*2t