What is the tangent of f(x)= 8/(x^2),\at x=2 ?

The tangent of f(x)= 8/(x^2),\at x=2 is y=-2x+6

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tangent of f(x)= 8/(x^2),\at x=2

tangent of

f (x) = \frac{8}{x ^{2}}, at x = 2

y = - 2 x + 6

Solution steps

Find the tangent point:

(2, 2)

Find the slope of

f (x) = \frac{8}{x ^{2}} : \frac{df ( x )}{d x} = - \frac{16}{x ^{3}}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = - 2

Find the line with slope m=

- 2

and passing through

(2, 2) : y = - 2 x + 6

y = - 2 x + 6

What is the tangent of f(x)= 8/(x^2),\at x=2 ?
The tangent of f(x)= 8/(x^2),\at x=2 is y=-2x+6