What is the derivative of x^2+4/x-10 ?

The derivative of x^2+4/x-10 is 2x-4/(x^2)

What is the first derivative of x^2+4/x-10 ?

The first derivative of x^2+4/x-10 is 2x-4/(x^2)

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\frac{d}{d x} (x^{2} + \frac{4}{x} - 10)

2 x - \frac{4}{x ^{2}}

Solution steps

\frac{d}{d x} (x^{2} + \frac{4}{x} - 10)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{2}) + \frac{d}{d x} (\frac{4}{x}) - \frac{d}{d x} (10)

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (\frac{4}{x}) = - \frac{4}{x ^{2}}

\frac{d}{d x} (10) = 0

= 2 x - \frac{4}{x ^{2}} - 0

Simplify

= 2 x - \frac{4}{x ^{2}}

What is the derivative of x^2+4/x-10 ?
The derivative of x^2+4/x-10 is 2x-4/(x^2)
What is the first derivative of x^2+4/x-10 ?
The first derivative of x^2+4/x-10 is 2x-4/(x^2)