What is the solution for (dy)/(dx)=(2x(y-1))/(x^2+1) ?

The solution for (dy)/(dx)=(2x(y-1))/(x^2+1) is y=e^{c_{1}}x^2+e^{c_{1}}+1

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(dy)/(dx)=(2x(y-1))/(x^2+1)

\frac{d y}{d x} = \frac{2 x ( y - 1 )}{x ^{2} + 1}

y = e^{c_{1}} x^{2} + e^{c_{1}} + 1

Solution steps

\frac{d y}{d x} = \frac{2 x ( y - 1 )}{x ^{2} + 1}

Solve separable ODE:

y = e^{c_{1}} x^{2} + e^{c_{1}} + 1

y = e^{c_{1}} x^{2} + e^{c_{1}} + 1

\int_{1}^{10} x ln (x) d x

x \to \infty lim (3 x - 9 x^{2} + x)

\int \frac{3 x - 1}{x ^{2} + 10 x + 28} d x

x^{2} sin^{6} (x) + x cos^{- 3} (x)

\frac{d}{d x} (\frac{e ^{2 x}}{e ^{2 x} + 1})

What is the solution for (dy)/(dx)=(2x(y-1))/(x^2+1) ?
The solution for (dy)/(dx)=(2x(y-1))/(x^2+1) is y=e^{c_{1}}x^2+e^{c_{1}}+1