(\partial)/(\partial x)(3x^2y^2-1)

Lösung

\frac{\partial}{\partial x} (3 x^{2} y^{2} - 1)

6 x y^{2}

Schritte zur Lösung

\frac{\partial}{\partial x} (3 x^{2} y^{2} - 1)

Behandle

y

als Konstante

Wende die Summen-/Differenzregel an:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (3 x^{2} y^{2}) - \frac{\partial}{\partial x} (1)

\frac{\partial}{\partial x} (3 x^{2} y^{2}) = 6 y^{2} x

\frac{\partial}{\partial x} (1) = 0

= 6 y^{2} x - 0

Vereinfache

= 6 x y^{2}

ma c l a u r in x^{2} - 1

n = 2 \sum \infty \frac{1}{n ( n + 1 )}

\int x^{\frac{- 2}{3}} x^{\frac{1}{3}} - 2 d x

\int \frac{d s}{s ^{2} ( s - 1 ) ^{2}} d x

\frac{d}{d x} (\frac{2}{x} - \frac{3 x}{3})