(dy)/(dx)=((3x+2y))/(3x+2y+2)

Lösung

\frac{d y}{d x} = \frac{( 3 x + 2 y )}{3 x + 2 y + 2}

y = \frac{2 W ( \frac{1}{4 e ^{\frac{- 25 x - c _{1}}{4}}} ) - 3}{5} - \frac{3 x}{2}

Schritte zur Lösung

\frac{d y}{d x} = \frac{( 3 x + 2 y )}{3 x + 2 y + 2}

Solve using substitution:

y = \frac{2 W ( \frac{1}{4 e ^{\frac{- 25 x - c _{1}}{4}}} ) - 3}{5} - \frac{3 x}{2}

y = \frac{2 W ( \frac{1}{4 e ^{\frac{- 25 x - c _{1}}{4}}} ) - 3}{5} - \frac{3 x}{2}

\frac{\partial}{\partial x} (x^{4} + x \cdot sin (y))

\int \frac{1}{x ( x - 2 )} d x

\int \frac{6400 q}{16 q ^{2} + 3200} d q

\frac{d}{d x} (\frac{x ^{2} ( x ^{3} - 1 )}{x ^{2} + 1})

d er i v a t i v e f (x) = 8 x + x^{2} + 7 x + 3