derivative f(1)=9+3/x

解答

导数

f (1) = 9 + \frac{3}{x}

- \frac{3}{x ^{2}}

求解步骤

\frac{d}{d x} (9 + \frac{3}{x})

使用微分加减法定则:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (9) + \frac{d}{d x} (\frac{3}{x})

\frac{d}{d x} (9) = 0

\frac{d}{d x} (\frac{3}{x}) = - \frac{3}{x ^{2}}

= 0 - \frac{3}{x ^{2}}

化简

= - \frac{3}{x ^{2}}

d er i v a t i v e f (x) = 3 x + 8

\frac{d}{d x} (\frac{4 - x ^{2}}{3 x - 2})

y^{^{'}} = \frac{- 1}{x ^{2}}

n = 0 \sum \infty \frac{1}{5} \cdot (- \frac{2}{3})^{n}

t an g e n t x^{2} + y^{2} = 25, (- 4, 3)