What is the limit as x approaches 0 of (5^{x+1}-5)/x ?

The limit as x approaches 0 of (5^{x+1}-5)/x is 5ln(5)

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limit as x approaches 0 of (5^{x+1}-5)/x

x \to 0 lim (\frac{5 ^{x + 1} - 5}{x})

5 ln (5)

Decimal

8.04718 \dots

Solution steps

x \to 0 lim (\frac{5 ^{x + 1} - 5}{x})

Apply L'Hopital's Rule

= x \to 0 lim (\frac{ln ( 5 ) \cdot 5 ^{x + 1}}{1})

Plug in the value

x = 0

= \frac{ln ( 5 ) \cdot 5 ^{0 + 1}}{1}

Simplify

= 5 ln (5)

What is the limit as x approaches 0 of (5^{x+1}-5)/x ?
The limit as x approaches 0 of (5^{x+1}-5)/x is 5ln(5)