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Popular Calculus >

integral from 0 to 1 of (6x+1)

Solution

\int_{0}^{1} (6 x + 1) d x

Solution

4

Solution steps

\int_{0}^{1} 6 x + 1 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{1} 6 x d x + \int_{0}^{1} 1 d x

\int_{0}^{1} 6 x d x = 3

\int_{0}^{1} 1 d x = 1

= 3 + 1

Simplify

= 4

Graph

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Frequently Asked Questions (FAQ)

What is the integral from 0 to 1 of (6x+1) ?
The integral from 0 to 1 of (6x+1) is 4