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受欢迎的微积分 >

tangent 3x^4+x^3-21x^2

解答

切线

3 x^{4} + x^{3} - 21 x^{2}

解答

y = (12 a_{0}^{3} + 3 a_{0}^{2} - 42 a_{0}) x - 9 a_{0}^{4} - 2 a_{0}^{3} + 21 a_{0}^{2}

求解步骤

计算在一般点

x = a_{0}

的切线

找到切点:

(a_{0}, 3 a_{0}^{4} + a_{0}^{3} - 21 a_{0}^{2})

计算

y = 3 x^{4} + x^{3} - 21 x^{2}

的斜率:

\frac{d y}{d x} = 12 x^{3} + 3 x^{2} - 42 x

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = 12 a_{0}^{3} + 3 a_{0}^{2} - 42 a_{0}

找到斜率 m=

12 a_{0}^{3} + 3 a_{0}^{2} - 42 a_{0}

且穿过

(a_{0}, 3 a_{0}^{4} + a_{0}^{3} - 21 a_{0}^{2})

的直线:

y = (12 a_{0}^{3} + 3 a_{0}^{2} - 42 a_{0}) x - 9 a_{0}^{4} - 2 a_{0}^{3} + 21 a_{0}^{2}

y = (12 a_{0}^{3} + 3 a_{0}^{2} - 42 a_{0}) x - 9 a_{0}^{4} - 2 a_{0}^{3} + 21 a_{0}^{2}

作图

流行的例子

tangent y=sqrt(x)(25.5)

t an g e n t y = x (25.5)

t an g e n t 7 x^{2}

奇偶性 y=(arcsin(sec(x)))^{tanh(x)}

p a r i t y y = (arcsin (sec (x)))^{t a n h (x)}

derivative f(x)= 6/(\sqrt[9]{x^7+5)}

d er i v a t i v e f (x) = \frac{6}{9 x ^{7} + 5}

integral of (ax+b)

\int (a x + b) d x