What is area y=x^2-1,y=-x+2,x=0,x=1 ?

The answer to area y=x^2-1,y=-x+2,x=0,x=1 is 13/6

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area y=x^2-1,y=-x+2,x=0,x=1

area

y = x^{2} - 1, y = - x + 2, x = 0, x = 1

\frac{13}{6}

Decimal

2.16666 \dots

Solution steps

Apply the area formula:

\int_{0}^{1} x^{2} - 1 - (- x + 2) d x

Solve

\int_{0}^{1} x^{2} - 1 - (- x + 2) d x : \frac{13}{6}

The area is:

= \frac{13}{6}

What is area y=x^2-1,y=-x+2,x=0,x=1 ?
The answer to area y=x^2-1,y=-x+2,x=0,x=1 is 13/6