What is the solution for (2x^2y+2sqrt(1+x^4y^2))dx+x^3dy=0 ?

The solution for (2x^2y+2sqrt(1+x^4y^2))dx+x^3dy=0 is y= 1/(c_{1)x^4}-(c_{1})/4

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(2x^2y+2sqrt(1+x^4y^2))dx+x^3dy=0

(2 x^{2} y + 2 1 + x^{4} y^{2}) d x + x^{3} d y = 0

y = \frac{1}{c _{1} x ^{4}} - \frac{c _{1}}{4}

Solution steps

(2 x^{2} y + 2 1 + x^{4} y^{2}) d x + x^{3} d y = 0

Solve using substitution:

y = \frac{1}{c _{1} x ^{4}} - \frac{c _{1}}{4}

y = \frac{1}{c _{1} x ^{4}} - \frac{c _{1}}{4}

\frac{d}{d x} ((4 x + 3)^{4} (x + 1)^{- 3})

\frac{d q}{d t} + \frac{1}{5 \cdot 1 0 ^{- 9}} q = \frac{200}{1000}

\int \frac{( ln ^{6} ( x ) )}{x} d x

\frac{d}{d x} (e^{(x + y)} - 1)

f (x) = (1 + 5 x)^{9}, (0, 1)

What is the solution for (2x^2y+2sqrt(1+x^4y^2))dx+x^3dy=0 ?
The solution for (2x^2y+2sqrt(1+x^4y^2))dx+x^3dy=0 is y= 1/(c_{1)x^4}-(c_{1})/4