What is the derivative of x^4-2x^2 ?

The derivative of x^4-2x^2 is 4x^3-4x

What is the first derivative of x^4-2x^2 ?

The first derivative of x^4-2x^2 is 4x^3-4x

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\frac{d}{d x} (x^{4} - 2 x^{2})

4 x^{3} - 4 x

Solution steps

\frac{d}{d x} (x^{4} - 2 x^{2})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{4}) - \frac{d}{d x} (2 x^{2})

\frac{d}{d x} (x^{4}) = 4 x^{3}

\frac{d}{d x} (2 x^{2}) = 4 x

= 4 x^{3} - 4 x

\int \frac{3 + 6 sinh ( x )}{x + 2 cosh ( x )} d x

t a y l or (1 - x^{2})^{(\frac{1}{2})}

d er i v a t i v e y = 3 x - 5

\frac{\partial}{\partial y} (ln (2 x + y))

\frac{d}{d x} ((x^{2} + y^{2}) e^{x^{2} + y^{2}})

What is the derivative of x^4-2x^2 ?
The derivative of x^4-2x^2 is 4x^3-4x
What is the first derivative of x^4-2x^2 ?
The first derivative of x^4-2x^2 is 4x^3-4x