What is laplacetransform-9t^2 ?

The answer to laplacetransform-9t^2 is -(18)/(s^3)

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laplacetransform-9t^2

laplace transform

- 9 t^{2}

- \frac{18}{s ^{3}}

Solution steps

L {- 9 t^{2}}

Use the constant multiplication property of Laplace Transform:

For function

f (t)

and constant

a : L {a \cdot f (t)} = a \cdot L {f (t)}

= - 9 L {t^{2}}

L {t^{2}} : \frac{2}{s ^{3}}

= - 9 \cdot \frac{2}{s ^{3}}

Refine

- 9 \frac{2}{s ^{3}} : - \frac{18}{s ^{3}}

= - \frac{18}{s ^{3}}

\int \frac{3 x}{1 + x ^{2}} d x

\int (- 2 x) d x

\frac{\partial}{\partial x} (x + y^{3})

\frac{\partial}{\partial x} (2 y x - 3 y + y^{2})

y e^{x y} d x + x e^{x y} d y = 0

What is laplacetransform-9t^2 ?
The answer to laplacetransform-9t^2 is -(18)/(s^3)