What is (\partial)/(\partial x)(xy+cos(x)) ?

The answer to (\partial)/(\partial x)(xy+cos(x)) is y-sin(x)

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(\partial)/(\partial x)(xy+cos(x))

\frac{\partial}{\partial x} (x y + cos (x))

y - sin (x)

Solution steps

\frac{\partial}{\partial x} (x y + cos (x))

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (x y) + \frac{\partial}{\partial x} (cos (x))

\frac{\partial}{\partial x} (x y) = y

\frac{\partial}{\partial x} (cos (x)) = - sin (x)

= y - sin (x)

\frac{d}{d x} f (x) = (2 x - 6)^{2} (x^{2} + x + 1)^{2}

\frac{d}{d x} (\frac{4}{sin ( x ) + cos ( x )})

\int cos (x) - 9 sin (x) d x

\int \frac{5}{x + 5 + x} d x

a re a f (x) = x + 3, [0, 9]

What is (\partial)/(\partial x)(xy+cos(x)) ?
The answer to (\partial)/(\partial x)(xy+cos(x)) is y-sin(x)