(4xy+3y^2-x)dx+x(x+2y)dy=0

Lösung

(4 x y + 3 y^{2} - x) d x + x (x + 2 y) d y = 0

y = \frac{- x ^{3} + x ( x ^{5} + x ^{4} + c _{1} )}{2 x ^{2}}, y = - \frac{x ^{3} + x ( x ^{5} + x ^{4} + c _{1} )}{2 x ^{2}}

Schritte zur Lösung

(4 x y + 3 y^{2} - x) d x + x (x + 2 y) d y = 0

Solve exact ODE:

y = \frac{- x ^{3} + x ( x ^{5} + x ^{4} + c _{1} )}{2 x ^{2}}, y = - \frac{x ^{3} + x ( x ^{5} + x ^{4} + c _{1} )}{2 x ^{2}}

y = \frac{- x ^{3} + x ( x ^{5} + x ^{4} + c _{1} )}{2 x ^{2}}, y = - \frac{x ^{3} + x ( x ^{5} + x ^{4} + c _{1} )}{2 x ^{2}}

\int 2 x e^{x^{2}} d x

t a y l or \frac{1}{( 1 + x ) ^{2}}, 0

\int_{- 6}^{0} (\frac{y}{6} + y + 7) d y

\int + \frac{1}{1 - 3 y} d y

n = 0 \sum \infty (\frac{4}{7})^{\frac{n}{2}}