What is the derivative of f(x)=1-(49)/(x^2) ?

The derivative of f(x)=1-(49)/(x^2) is (98)/(x^3)

What is the first derivative of f(x)=1-(49)/(x^2) ?

The first derivative of f(x)=1-(49)/(x^2) is (98)/(x^3)

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derivative of

f (x) = 1 - \frac{49}{x ^{2}}

\frac{98}{x ^{3}}

Solution steps

\frac{d}{d x} (1 - \frac{49}{x ^{2}})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (1) - \frac{d}{d x} (\frac{49}{x ^{2}})

\frac{d}{d x} (1) = 0

\frac{d}{d x} (\frac{49}{x ^{2}}) = - \frac{98}{x ^{3}}

= 0 - (- \frac{98}{x ^{3}})

Simplify

= \frac{98}{x ^{3}}

\int x^{- 11} d x

\int \frac{2}{4 x ^{3}} d x

t an g e n t f (x) = \frac{3 x}{x + 1}, (2, 2)

\int_{0}^{3} x 1 + 2 x d x

\int (y^{2} + ln (x)) d y

What is the derivative of f(x)=1-(49)/(x^2) ?
The derivative of f(x)=1-(49)/(x^2) is (98)/(x^3)
What is the first derivative of f(x)=1-(49)/(x^2) ?
The first derivative of f(x)=1-(49)/(x^2) is (98)/(x^3)