integral of (sec^2(θ)+6)

解答

\int (sec^{2} (θ) + 6) d θ

tan (θ) + 6 θ + C

求解步骤

\int sec^{2} (θ) + 6 d θ

使用积分加法定则:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int sec^{2} (θ) d θ + \int 6 d θ

\int sec^{2} (θ) d θ = tan (θ)

\int 6 d θ = 6 θ

= tan (θ) + 6 θ

解答补常数

= tan (θ) + 6 θ + C

d er i v a t i v e 1 - 2 sin^{2} (x)

t an g e n t y = (\frac{x + 3}{x - 1})^{2}, (5, 4)

f (x) = sin (x) + arcsin (x)

\frac{d}{d x} (lo g_{2} (5 x))

\int \frac{3 + 2 x ^{2}}{x ^{2}} d x